x^2+144+4x^2=27

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Solution for x^2+144+4x^2=27 equation: 



x^2+144+4x^2=27

We move all terms to the left:

x^2+144+4x^2-(27)=0

We add all the numbers together, and all the variables

5x^2+117=0

a = 5; b = 0; c = +117;
Δ = b2-4ac
Δ = 02-4·5·117
Δ = -2340
Delta is less than zero, so there is no solution for the equation

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